So, for reducing radicals Mr. Kelly has a certain method. Let's say we have √500. What would Mr. Kelly do?
Well, we would take 500 and divide it my the lowest number it divides into, like 2. It's look a little like...
500/2=250
250/2=125
125/5=25
25/5=5
5/5=1
Now you wanna get the pairs... like there is one pair of 2's, and there is one pair of 5, with a 5 left over 5.
You'd keep the left over 5 inside the square root while the 5 and the 2 go on the outside. Since the numbers are next to each other, that signifies that you need to multiply them. So in the end, you'd have 10√5.
Well, we would take 500 and divide it my the lowest number it divides into, like 2. It's look a little like...
500/2=250
250/2=125
125/5=25
25/5=5
5/5=1
Now you wanna get the pairs... like there is one pair of 2's, and there is one pair of 5, with a 5 left over 5.
You'd keep the left over 5 inside the square root while the 5 and the 2 go on the outside. Since the numbers are next to each other, that signifies that you need to multiply them. So in the end, you'd have 10√5.